https://file.aiquickdraw.com/mathbot/file/17265748591097bf83x8a.jpg

Let's solve the problem given in the image:

We need to evaluate \((6 \times 10^2) \div (3 \times 10^{-5})\), and express the result in standard form.

### Step-by-step Solution:

1. First, express the division of the constants and powers of 10 separately:
   \[
   \frac{6 \times 10^2}{3 \times 10^{-5}} = \frac{6}{3} \times \frac{10^2}{10^{-5}}
   \]

2. Simplify the constants:
   \[
   \frac{6}{3} = 2
   \]

3. For the powers of 10, apply the laws of exponents:
   \[
   \frac{10^2}{10^{-5}} = 10^{2 - (-5)} = 10^{2 + 5} = 10^7
   \]

4. Now, combine the results:
   \[
   2 \times 10^7
   \]

### Final Answer:
The result is \(2 \times 10^7\).

This is already in standard form.

Let me know if you want any further clarifications or details!

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Here are 5 related questions for practice:
1. How would you solve \((9 \times 10^3) \div (3 \times 10^{-4})\)?
2. What is \((8 \times 10^5) \div (4 \times 10^{-3})\)?
3. How do you multiply \((7 \times 10^2) \times (2 \times 10^4)\)?
4. What are the rules for multiplying and dividing powers of 10?
5. How do you convert a number like 0.0025 into standard form?

**Tip:** When dividing terms with powers of 10, always subtract the exponents.

Work out (6 × 10^2) ÷ (3 × 10^-5) and give your answer in standard form.

Learn how to solve the division problem (6 × 10^2) ÷ (3 × 10^-5) using the laws of exponents and express the answer in standard form. Suitable for students in Grades 8-10.

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